Invert a binary tree.
4 / \ 2 7 / \ / \ 1 3 6 9to
4 / \ 7 2 / \ / \ 9 6 3 1
Solution:
public TreeNode invertTree(TreeNode root) {
if (root == null) {
return null;
}
final TreeNode left = root.left,
right = root.right;
root.left = invertTree(right);
root.right = invertTree(left);
return root;
}
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