Given a set of non-negative integers, and a value sum, determine if there is a subset of the given set with sum equal to given sum.
Examples: set[] =
{3, 34, 4, 12, 5, 2}, sum = 9
Output: True //There is a subset (4, 5) with sum 9.
Let isSubSetSum(int
set[], int n, int sum) be the function to find whether there is a subset of
set[] with sum equal to sum. n is the
number of elements in set[].
The isSubsetSum
problem can be divided into two subproblems
…a) Include the
last element, recur for n = n-1, sum = sum – set[n-1]
…b) Exclude the
last element, recur for n = n-1.
If any of the above
subproblems return true, then return true.
Following is the
recursive formula for isSubsetSum() problem.
isSubsetSum(set,
n, sum) = isSubsetSum(set, n-1, sum) ||
isSubsetSum(arr, n-1, sum-set[n-1])
Base Cases:
isSubsetSum(set, n, sum) = false, if sum > 0 and n == 0
isSubsetSum(set, n, sum) = true, if sum == 0
Sol:
public static boolean subSetSum(int[] a, int n, int sum) {
if(sum == 0) {
return true;
}
if(n == 0 && sum != 0) {
return false;
}
if(a[n]>sum) {
subSetSum(a, n-1, sum);
}
return subSetSum(a, n-1, sum-a[n]) || subSetSum(a, n-1, sum);
}
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