Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).
For example:
Given binary tree
Given binary tree
[3,9,20,null,null,15,7]
,3 / \ 9 20 / \ 15 7
return its bottom-up level order traversal as:
[ [15,7], [9,20], [3] ]Ans:
public List<List<Integer>> levelOrderBottom(TreeNode root) {
Queue<TreeNode> queue = new LinkedList<TreeNode>();
List<List<Integer>> result = new LinkedList<List<Integer>>();
if(root == null) {
return result;
}
queue.add(root);
while(!queue.isEmpty()) {
int size = queue.size();
List<Integer> tempList = new LinkedList<Integer>();
for(int i=0; i<size; i++) {
TreeNode temp = queue.poll();
if(temp.left != null) {
queue.add(temp.left);
}
if(temp.right != null) {
queue.add(temp.right);
}
tempList.add(temp.val);
}
result.add(0, tempList);
}
return result;
}
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