Given n
non-negative integers a1, a2, ..., an
, where each represents a point at coordinate (i, ai)
. n
vertical lines are drawn such that the two endpoints of the line i
is at (i, ai)
and (i, 0)
. Find two lines, which, together with the x-axis forms a container, such that the container contains the most water.
Notice that you may not slant the container.
Example 1:
Input: height = [1,8,6,2,5,4,8,3,7] Output: 49 Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
Example 2:
Input: height = [1,1] Output: 1
Example 3:
Input: height = [4,3,2,1,4] Output: 16
Example 4:
Input: height = [1,2,1] Output: 2
Solution
public int maxArea(int[] height) { int maxArea=0; for(int i=0, j=height.length-1; i< j; ) { int tempArea = Math.min(height[i],height[j])*(j-i); if(tempArea>maxArea) { maxArea=tempArea; } if(height[i]<height[j]) { i++; } else { j--; } } return maxArea; }
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