Print matrix in Spiral Order

Print matrix in Spiral Order

Problem:
Given a matrix of m x n elements (m rows, n columns), write a function that prints the elements in the matrix in a spiral manner.

Solution:

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void spiralOrder(int a[][], int m, int n, int k) {   if (m <= 0 || n <= 0)     return;   if (m == 1) {     for (int j = 0; j < n; j++)       system.out.print(a[k][k+j] + " ");     return;   }   if (n == 1) {     for (int i = 0; i < m; i++)       system.out.print(a[k+i][k] + " ");     return;   }   // print from top left   for (int j = 0; j < n - 1; j++)     system.out.print(a[k][k+j] + " ");   // print from top right   for (int i = 0; i < m - 1; i++)     system.out.print(a[k+i][k+n-1] + " ");   // print from bottom right   for (int j = 0; j < n - 1; j++)     system.out.print(a[k+m-1][k+n-1-j] + " ");   // print from bottom left   for (int i = 0; i < m - 1; i++)     system.out.print(a[k+m-1-i][k] + " ");      print_spiral(a, m-2, n-2, k+1); }