Sort 3 numbers array
Sort an array which has values 1, 2 and 3 with n comparisons only.
input : {1,2,3,2,3,1,2,3,3,2,2,2,3,1,2,1,1,3,3,2,2,1,2,2,3,2,2,2,1,3,1}
output: 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3
input : {1,2,3,2,3,1,2,3,3,2,2,2,3,1,2,1,1,3,3,2,2,1,2,2,3,2,2,2,1,3,1}
output: 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3
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| // Sort an array which has numbers 1, 2 and 3int[] Sort(int[] a){ int i,j; for(i=0,j=a.length-1; i<j;) { if(a[i]==1) { i++; } else if(a[j]==3) { j--; } else if(a[i]>a[j] && a[i]==3) { Swap(a,i,j); } else if(a[i]>a[j] && a[j]==1) { Swap(a,i,j); } else { // both values are 2 int k=i+1; while(a[k]==a[j] && k<j) { k++; } if(j==k) break; else if(a[k]<a[i] && a[k]==1) { Swap(a,k,i); i++; } else if(a[k]>a[j]&&a[k]==3) { Swap(a,k,j); j--; } } } return a;}void Swap(int[] a, int i, int j){ int temp=a[i]; a[i]=a[j]; a[j]=temp;} |
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