Reverse alternative order of words in a sentence

Reverse alternative order of words in a sentence

Reverse alternative order of words in a sentence.

Problem:
Reverse alternative order of words in a sentence.
i/p: This is for testing
o/p: is This testing for

Solution:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47

void reverse(char *s, char *t) {  for( ; s < t; s++, t--) {    char temp = *s;         *s = *t;         *t = temp;  } }   reverseWords(char *s) {   char *wordBegin = NULL;   char *temp = s;   char *stcBegin = s;   int wordCount = 0;   while(*temp) {     if(wordBegin == NULL && *temp != ' ') {       wordBegin = temp;        if(wordCount==0) {          stcBegin = temp;       }        }     else if (wordBegin && *(temp+1)==' ' ||  *(temp+1)=='\0') {       reverse(wordBegin, temp);       wordBegin = NULL;       wordCount++;        }     if(wordCount>0 && wordCount%2==0) {         reverse(stcBegin, temp);         wordCount=0;     }       temp++;   }         }       int main() {   char s[] = "This is for testing";   char *temp = s;   reverseWords(s);   printf("%s", s);    return 0; }

Click here for more Programming Interview Questions